2c^2-16c+24=

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Solution for 2c^2-16c+24= equation:


Simplifying
2c2 + -16c + 24 = 0

Reorder the terms:
24 + -16c + 2c2 = 0

Solving
24 + -16c + 2c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '2'.
2(12 + -8c + c2) = 0

Factor a trinomial.
2((2 + -1c)(6 + -1c)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Subproblem 2

Set the factor '(6 + -1c)' equal to zero and attempt to solve: Simplifying 6 + -1c = 0 Solving 6 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1c = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1c = 0 + -6 -1c = 0 + -6 Combine like terms: 0 + -6 = -6 -1c = -6 Divide each side by '-1'. c = 6 Simplifying c = 6

Solution

c = {2, 6}

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